3x^2-30x=62

Solution for 3x^2-30x=62 equation:

3x^2-30x=62

We move all terms to the left:

3x^2-30x-(62)=0

a = 3; b = -30; c = -62;
Δ = b2-4ac
Δ = -302-4·3·(-62)
Δ = 1644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1644}=\sqrt{4*411}=\sqrt{4}*\sqrt{411}=2\sqrt{411}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{411}}{2*3}=\frac{30-2\sqrt{411}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{411}}{2*3}=\frac{30+2\sqrt{411}}{6}
$